x^(4/3)-29x^(2/3)+100=0

Solution for x^(4/3)-29x^(2/3)+100=0 equation:

x in (-oo:+oo)

x^(4/3)-(29*x^(2/3))+100 = 0

x^(4/3)-29*x^(2/3)+100 = 0

t_1 = x^(2/3)

1*t_1^2-29*t_1^1+100 = 0

t_1^2-29*t_1+100 = 0

DELTA = (-29)^2-(1*4*100)

DELTA = 441

DELTA > 0

t_1 = (441^(1/2)+29)/(1*2) or t_1 = (29-441^(1/2))/(1*2)

t_1 = 25 or t_1 = 4

t_1 = 4

x^(2/3)-4 = 0

1*x^(2/3) = 4 // : 1

x^(2/3) = 4

x^(2/3) = 4 // ^ 3

x^2 = 64 // ^ 1/2

abs(x) = 8

x = 8 or x = -8

t_1 = 25

x^(2/3)-25 = 0

1*x^(2/3) = 25 // : 1

x^(2/3) = 25

x^(2/3) = 25 // ^ 3

x^2 = 15625 // ^ 1/2

abs(x) = 125

x = 125 or x = -125

x in { 8, -8, 125, -125 }